Let the volumetric analysis of gaseous fuel be known. The chemical equations for gaseous fuel are as follows:
- 2H2 + O2 → 2H2O2 volumes of H2 + 1 volume of O2 → 2 volumes of H2Oor 1 volume of H2 +
volume of O2 → 1 volume of H2O - 2CO + O2 → 2CO22 volumes of CO + 1 volume of O2 → 2 volumes of CO2
- CH4 + 2O2 → 2H2O + CO21 volume of CH4 + 2 volumes of O2 → 2 volumes of H2O + 1 volume of CO2
- C2H4 + 3O2 → 2H2O + 2CO21 volume of C2H4 + 3 volumes of O2 → 2 volumes of H2O + 2 volumes of CO2
Let the volume fraction of the gaseous fuel contain H2, CO, CH4, C2H4, CO2, and N2, the last two being incombustible gases.
The quantity of O2 required
m3/m3 of gas
Air contains 21% of O2 by volume.
Quantity of air required ![]()

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